Timeline for Determining R-S configuration with lowest priority groups in plane of paper
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 21 at 16:14 | vote | accept | Techie5879 | ||
| Sep 8, 2021 at 16:26 | history | bounty ended | Techie5879 | ||
| Sep 5, 2021 at 13:18 | comment | added | user55119 | Fair enough. BTW, I should have said above, "Oh look! They are mirror images". | |
| Sep 5, 2021 at 8:34 | comment | added | Techie5879 | Okay, this matches with my conclusion then. I'll wait a bit for another answer, if I see any change of conclusion as to whether there are enantiomers or homomers, and if not I'll accept this answer. Hope thats fair. | |
| Sep 4, 2021 at 23:23 | comment | added | user55119 | Change of mind. The Fischer projections of the hexahalide are linked in the ADDENDUM. | |
| Sep 4, 2021 at 23:17 | history | edited | user55119 | CC BY-SA 4.0 |
Added ADDENDUM.
|
| Sep 4, 2021 at 22:46 | comment | added | user55119 | The person who wrote the question was not necessarily the person who provided the answers. They may have simply placed a mirror plane between A and B and said, "Oh look! they are images. Therefore, they are enantiomers." Nonsense, they are identical meso compounds. I could draw Fischer projections but they are more suitable for carbon chains greater than two. | |
| Sep 4, 2021 at 22:01 | comment | added | Techie5879 | Yes your interpretation of homomers is correct. Also, this is the same answer I am getting, but the answer in the book says they are enantiomers and apparently drawing the Fischer projection gives opposite configurations at the carbons? Could you also update your answer with what the Fischer projection of the two molecules would be? | |
| Sep 4, 2021 at 21:12 | history | answered | user55119 | CC BY-SA 4.0 |