Timeline for Finding the pOH of a buffer from the scratch without the Henderson Hasselbalch equation
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| May 13, 2021 at 6:58 | comment | added | Floatoss | I did calculate that, you can see it below the reaction I wrote up, I wrote that 0.1 mol of $\ce{(NH_4)_2 SO_4}$ gives 0.2 mol of $\ce{NH_4^{+}}$. | |
| May 13, 2021 at 6:30 | comment | added | Mathew Mahindaratne | To me it seems like you have not counted each molecule of $\ce{(NH4)2SO4}$ gives 2 ions of $\ce{NH4+}$. Therefore, $[\ce{NH4+}]$ of the solution is $\pu{0.4 M}$ (not $\pu{0.2 M}$; see my calculations). | |
| May 13, 2021 at 6:01 | comment | added | Floatoss | That makes sense to me now, thank you. But I still don't know the "extra factor" of 0.5 I had in the way where I did not convert into standard concentration. Is there an explanation to that? | |
| May 13, 2021 at 5:58 | comment | added | Mathew Mahindaratne | $\pu{1 M} = \pu{1 mol L-1}$. Your solutions are $\pu{0.1 mol}$ in $\pu{0.5 L}$ for both compounds. So, $\pu{M} = \frac{\pu{mol}}{\pu{L}}$, and do your calculations. | |
| May 13, 2021 at 5:45 | comment | added | Floatoss | Thank you for your reply. But why did you bring the "0.2 M" is what I am not able to understand. As in you wrote 0.2 mol of $\ce{NH_4OH}$ where as it was given that it was 0.1 mol in the question. I thought what you might have done would be "if 0.1 mol in 500mL then, 0.2 mol in 1L". Am I missing something? What I wanted to discuss was the "extra factor of 0.5" I had when I solved it the way I explained. | |
| May 13, 2021 at 5:38 | history | edited | Mathew Mahindaratne | CC BY-SA 4.0 |
added 103 characters in body
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| May 13, 2021 at 5:33 | comment | added | Mathew Mahindaratne | Didn't you see I have calculated the initial concentration in first hand so I don't have to deal with volumes? | |
| May 13, 2021 at 4:55 | comment | added | Floatoss | Why did you do the calculations considering everything happening for 1 litre of the stuff and not considering 500 mL itself? | |
| May 12, 2021 at 20:13 | history | answered | Mathew Mahindaratne | CC BY-SA 4.0 |