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Corrected mistake.
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LDC3
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The cyclic form of glucose uses the C5 oxygen for bonding since it forms a 6 member ring (more stable then either 5 or 7 member ring).

They are not isomers since $\ce{H2O}$ is liberated upon formingthey have the ringsame chemical formula.

The cyclic form of glucose uses the C5 oxygen for bonding since it forms a 6 member ring (more stable then either 5 or 7 member ring).

They are not isomers since $\ce{H2O}$ is liberated upon forming the ring.

The cyclic form of glucose uses the C5 oxygen for bonding since it forms a 6 member ring (more stable then either 5 or 7 member ring).

They are isomers since they have the same chemical formula.

Source Link
LDC3
  • 8.2k
  • 22
  • 42

The cyclic form of glucose uses the C5 oxygen for bonding since it forms a 6 member ring (more stable then either 5 or 7 member ring).

They are not isomers since $\ce{H2O}$ is liberated upon forming the ring.