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Timeline for Wave function of a perturbed system

Current License: CC BY-SA 4.0

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May 1, 2020 at 10:20 comment added porphyrin It has to be assumed that the derivatives behave normally, but as it happens its only a formal differentiation, and then integration; the wavefunction is only used symbolically. Only the unperturbed wavefunctions are used to calculate first order and the function for these (say sin, cos , exp etc. ) are known by solving the unperturbed equation, and as the $V$ is known and also the $E_n$ the wavefunction for $\varphi^{(1)}$ can be calculated.
May 1, 2020 at 9:24 comment added Manu As we use $d\psi_n/d\lambda$, it can happen that the wave function may not be continuous with respect to $\lambda$ or is not differentiable at a particular $\lambda$, because the postulates of quantum mechanics specify that wave function is continuous with respect to x,y and z, not with respect to some other quantity like extent of perturbation($\lambda$). Do we assume that $\psi$ is also continuous for $\lambda$?
May 1, 2020 at 9:02 history answered porphyrin CC BY-SA 4.0