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Apr 23, 2020 at 22:50 comment added HaLo2FrEeEk I guess I'll add sulfuric acid little by little with stirring. This really is just an experiment with leftover chemicals so...
Apr 23, 2020 at 15:20 comment added Maurice To recover copper carbonate, the excess carbonate must be destroyed, by adding an acid. The trouble is : first the excess carbonate ions will produce huge amounts of CO2. Then the anion $\ce{[Cu(CO_3)_2]^{2-}}$ will be decomposed and the malachite precipitate will soon appear again. But it is difficult to know with some precision the amount of acid necessary to obtain malachite quantitively, because if an excess of acid is added, the malachite will be dissolved and at the end you will obtain a $\ce{Cu^{2+}}$ solution like in the very beginning of your experiments.
Apr 23, 2020 at 8:48 comment added Maurice Your white precipitate may be sodium hydrogenocarbonate $\ce{NaHCO_3}$ which is not very soluble in water : $6.9$ g in $100$ mL, and less in $\ce{Na_2CO_3}$ solutions. This substance appears in $\ce{Na_2CO_3}$ solution exposed to air and/or to $\ce{CO_2}$
Apr 23, 2020 at 2:28 comment added HaLo2FrEeEk Wow, thank you for the very specific answer! I'm wondering, is there a way to somehow recover the copper carbonate/anion from the filtrate? After filtering I've let it sit in a wide mouth jar covered with a coffee filter and there's some white precipitate at the bottom and fractal-tree looking crystals crawling up the sides.
Apr 23, 2020 at 2:24 vote accept HaLo2FrEeEk
Apr 22, 2020 at 20:04 history edited Maurice CC BY-SA 4.0
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Apr 22, 2020 at 19:43 history edited Maurice CC BY-SA 4.0
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Apr 22, 2020 at 10:16 history answered Maurice CC BY-SA 4.0