Timeline for Finding EMF of a galvanic cell without standard potentials
Current License: CC BY-SA 4.0
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Jul 17, 2019 at 6:10 | comment | added | Karsten♦ | @DivMit $$\ce{Ag+(aq) + e- <=> Ag(s)}$$ is a balanced half reaction, and if it describes both half-cells, you get the chemical equation you have in your comment. The concentration of silver cations in the two half cells indirectly depends on the concentration of chloride or bromide (as you can see in the calculation). Writing it this way, however, chloride and bromide are not part of the electrochemical equation and so they don't appear in the reaction quotient Q of the Nernst equation directly. | |
Jul 17, 2019 at 5:03 | comment | added | Mr.HiggsBoson | @KarstenTheis Sir, you just said that E° = 0 but now by putting values you are saying that E°≠0, also this was an exam type situations so the E° was not given. Also, how did you write the equation 3 directly ie.$$\ce{Ag+(c) + Ag(b) <=> Ag(c) + Ag+(b)}$$ why did you ignore the Chloride/Bromide radicals from the equation ?? What I tried making was the equation from reaction 1 and 2 but since E° was not given I couldn't proceed. Please explain the equation 3. :) | |
Jul 17, 2019 at 4:07 | history | edited | Karsten♦ | CC BY-SA 4.0 |
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Jul 17, 2019 at 2:53 | comment | added | Ed V | Excellent, we got the same answer! The -0.173 V was using the OP's solubility product constants. Thanks for the clarification! | |
Jul 17, 2019 at 2:42 | comment | added | Karsten♦ | @EdV I wrote up the numerical answer calculated both ways. I gave myself some extra significant figures for the calculation of the solubility products. When you say "your expression", I think there was some misunderstanding. With a standard potential of 0 V and silver ion concentrations similar in both cells, I'm not sure how you got -0.173 V. In any case, you can see that the chloride and bromide concentrations are used both times because the reaction quotient contains the silver ion concentrations in one case, and the bromide and chloride ion concentrations in the other case. | |
Jul 17, 2019 at 2:33 | history | edited | Karsten♦ | CC BY-SA 4.0 |
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Jul 16, 2019 at 22:05 | history | edited | Karsten♦ | CC BY-SA 4.0 |
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Jul 16, 2019 at 21:58 | history | edited | Karsten♦ | CC BY-SA 4.0 |
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Jul 16, 2019 at 21:52 | history | edited | Karsten♦ | CC BY-SA 4.0 |
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Jul 16, 2019 at 21:32 | history | edited | Karsten♦ | CC BY-SA 4.0 |
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Jul 16, 2019 at 20:15 | vote | accept | Mr.HiggsBoson | ||
Jul 16, 2019 at 19:24 | history | edited | Karsten♦ | CC BY-SA 4.0 |
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Jul 16, 2019 at 18:54 | history | answered | Karsten♦ | CC BY-SA 4.0 |