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Jun 29, 2019 at 15:26 comment added Eashaan Godbole $\gamma_{c}\to 1$ would apply only for sparingly soluble solutes. The assumption would deviate further away from reality at higher $x_{c}$ values.
Jun 27, 2019 at 10:46 comment added LoschmidtsSchnitzel I think its hard / next to impossible to deduct a very general trend. However a high bp can point to hydrogen bonding, which would mean favourable interactions with water. For propanon / propanal your approach was right but I'd argue that the keton is so miscible because the oxygen is in a symmetrical central position, whereas the aldehyde has a hydrophilic and a hydrophobic end - maybe there is more, surprised it would have such a strong effect with a 3C chain length (that two-tail effect is used in tensides / soaps, where the chain length is around 12-18 Cs)
Jun 27, 2019 at 9:23 comment added Donkey Kong This is a bit too complex for my understanding (only a high school student) but what would you say for the solubility of comparable ketones and aldehydes? Is the boiling point not concrete evidence for higher solubility? Thanks!
Jun 26, 2019 at 19:32 comment added LoschmidtsSchnitzel I interpreted "higher boiling/melting point" as referring to both boiling and melting point
Jun 26, 2019 at 18:06 comment added Buck Thorn By the way, the OP asks about the connection between the boiling point and solubility, not the melting point.
Jun 26, 2019 at 15:51 comment added Buck Thorn Ok, maybe you want to edit for clarity.
Jun 26, 2019 at 15:20 comment added LoschmidtsSchnitzel Between solid solute and solvated solute. There is mechanical, thermal and chemical equilibrium and two distinct phases, so this is also a phase equilibrium
Jun 26, 2019 at 14:40 comment added Buck Thorn What do you mean with " phase equilibrium between a soluble compound C and water"?
Jun 26, 2019 at 10:29 history answered LoschmidtsSchnitzel CC BY-SA 4.0