Skip to main content
19 events
when toggle format what by license comment
S May 24, 2021 at 19:24 history bounty ended S R Maiti
S May 24, 2021 at 19:24 history notice removed S R Maiti
May 23, 2021 at 1:32 history edited Mathew Mahindaratne
edited tags
May 23, 2021 at 1:29 answer added Mathew Mahindaratne timeline score: 6
May 21, 2021 at 5:36 history protected andselisk
May 21, 2021 at 0:02 comment added anomeric ![enter image description here](i.sstatic.net/be2bA.png) This is from March 6th edition page 1610. Does this help? :)
May 20, 2021 at 21:42 answer added user213305 timeline score: 0
May 20, 2021 at 20:49 answer added anomeric timeline score: -2
May 20, 2021 at 20:16 comment added user55119 Now that a bounty has been placed on this post and a reputable source for the answer is requested, I seriously suspect that one will not be found. Any version of the Lossen rearrangement requires activation of the oxygen into a viable leaving group before base can effect deprotonation and alpha-elimination can occur to form the isocyanate. If the methyl carbamate is the desired product, simply treat the the activated hydroxamic acid with MeONa/MeOH rather than aqueous base.
S May 20, 2021 at 18:57 history bounty started S R Maiti
S May 20, 2021 at 18:57 history notice added S R Maiti Authoritative reference needed
Jul 1, 2019 at 13:59 comment added Curt F. Seems like methanol/methoxide nucleophilic attack on the isocyanate (instead of water/hydroxide) would lead to the carbamate. Not sure if that squares with the supposedly two-step reaction scheme though.
May 23, 2019 at 0:46 history edited Melanie Shebel CC BY-SA 4.0
formatting, grammar
May 10, 2019 at 18:04 comment added Waylander My thoughts. I think you have to deprotonate the NH of the hydroxamic acid and lose OH- to give the isocyanate analogous to the mechanism of the Lossen that you have drawn. This is the only option that makes any kind of sense, and it is known that deprotonation of hydroxamic acids proceeds at NH rather than OH.
May 10, 2019 at 6:00 history tweeted twitter.com/StackChemistry/status/1126728732750667778
May 9, 2019 at 21:16 comment added user55119 First deprotonate and then lose carboxylate. The remaining neutral species reranges to an isocyanate. In methanol the isocyanate forms the methyl ester of a carbamic acid. Compare the similarity of the Lossen and Hofmann rearrangements
May 9, 2019 at 20:35 history edited FullBridge CC BY-SA 4.0
added 9 characters in body
May 9, 2019 at 20:25 history edited FullBridge CC BY-SA 4.0
added 59 characters in body
May 9, 2019 at 20:20 history asked FullBridge CC BY-SA 4.0