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Feb 13, 2019 at 6:11 comment added andselisk @MaxW You are correct, I didn't want to overload the answer with obsolete standards and took the modern one. Even if you take former $\ce{^{16}O}$ standard, it wouldn't change the answer, but would cause unnecessary confusion IMO.
Feb 13, 2019 at 6:07 comment added MaxW I'll point out that $\ce{^{12}C}$ wasn't chosen as the standard until the 1960's in the 20th century.
Feb 13, 2019 at 5:51 vote accept ceno980
Feb 13, 2019 at 5:47 history answered andselisk CC BY-SA 4.0