Skip to main content
The lone pair of hydroxide ions, not water, will attack in basic medium.
Source Link

Going by the mechanism of hydrolysis under basic medium, the lone pair of waterhydroxide ion will attack on C=O carbon.

Due to the negative mesomeric (-M/-R) effect and negative inductive effect of the nitro group, the C=O will act as a more electrophilic substrate as compared to the one which is has ether substituent,

(which due to its +M and +I effect will reduce the electrophilic character of the C=O ),
will be easier to hydrolyse.

The effect of solvation on substituents is less likely to tell which compound will hydrolyse easily as it is not the Rate Determining Step of the reaction. So although the observation is not wrong, its still not the deciding factor.

Going by the mechanism of hydrolysis under basic medium, the lone pair of water will attack on C=O carbon.

Due to the negative mesomeric (-M/-R) effect and negative inductive effect of the nitro group, the C=O will act as a more electrophilic substrate as compared to the one which is has ether substituent,

(which due to its +M and +I effect will reduce the electrophilic character of the C=O ),
will be easier to hydrolyse.

The effect of solvation on substituents is less likely to tell which compound will hydrolyse easily as it is not the Rate Determining Step of the reaction. So although the observation is not wrong, its still not the deciding factor.

Going by the mechanism of hydrolysis under basic medium, the lone pair of hydroxide ion will attack on C=O carbon.

Due to the negative mesomeric (-M/-R) effect and negative inductive effect of the nitro group, the C=O will act as a more electrophilic substrate as compared to the one which is has ether substituent,

(which due to its +M and +I effect will reduce the electrophilic character of the C=O ),
will be easier to hydrolyse.

The effect of solvation on substituents is less likely to tell which compound will hydrolyse easily as it is not the Rate Determining Step of the reaction. So although the observation is not wrong, its still not the deciding factor.

Going by the mechanism of hydrolysis under basic medium, the lone pair of water will attack on C=O carbon.

Due to the negative mesomeric (-M/-R) effect and negative inductive effect of the nitro group, the C=O will act as a more electrophilic substrate as compared to the one which is has ether substituent,

(which due to its +M and +I effect will reduce the electrophilic character of the C=O  ),
will be easier to hydrolyse.

The effect of solvation on substientssubstituents is less likely to tell which compound will hydrolyse easily as it is not the Rate Determining StepRate Determining Step of the reaction. So although the observation is not wrong, its still not the deciding factor.

Going by the mechanism of hydrolysis under basic medium, the lone pair of water will attack on C=O carbon.

Due to the negative mesomeric (-M/-R) effect and negative inductive effect of the nitro group, the C=O will act as a more electrophilic substrate as compared to the one which is has ether substituent,

(which due to its +M and +I effect will reduce the electrophilic character of the C=O),
will be easier to hydrolyse.

The effect of solvation on substients is less likely to tell which compound will hydrolyse easily as it is not the Rate Determining Step of the reaction. So although the observation is not wrong, its still not the deciding factor.

Going by the mechanism of hydrolysis under basic medium, the lone pair of water will attack on C=O carbon.

Due to the negative mesomeric (-M/-R) effect and negative inductive effect of the nitro group, the C=O will act as a more electrophilic substrate as compared to the one which is has ether substituent,

(which due to its +M and +I effect will reduce the electrophilic character of the C=O  ),
will be easier to hydrolyse.

The effect of solvation on substituents is less likely to tell which compound will hydrolyse easily as it is not the Rate Determining Step of the reaction. So although the observation is not wrong, its still not the deciding factor.

added 236 characters in body
Source Link

Going by the mechanism of hydrolysis under basic medium, the lone pair of water will attack on C=O carbon.

Due to the negative mesomeric (-M/-R) effect and negative inductive effect of the nitro group, the C=O will act as a more electrophilic substrate as compared to the one which is has ether substituent,

(which due to its +M and +I effect will reduce the electrophilic character of the C=O),
will be easier to hydrolyse.

The effect of solvation on substients is less likely to tell which compound will hydrolyse easily as it is not the Rate Determining Step of the reaction. So although the observation is not wrong, its still not the deciding factor.

Going by the mechanism of hydrolysis under basic medium, the lone pair of water will attack on C=O carbon.

Due to the negative mesomeric (-M/-R) effect and negative inductive effect of the nitro group, the C=O will act as a more electrophilic substrate as compared to the one which is has ether substituent,

(which due to its +M and +I effect will reduce the electrophilic character of the C=O),
will be easier to hydrolyse.

Going by the mechanism of hydrolysis under basic medium, the lone pair of water will attack on C=O carbon.

Due to the negative mesomeric (-M/-R) effect and negative inductive effect of the nitro group, the C=O will act as a more electrophilic substrate as compared to the one which is has ether substituent,

(which due to its +M and +I effect will reduce the electrophilic character of the C=O),
will be easier to hydrolyse.

The effect of solvation on substients is less likely to tell which compound will hydrolyse easily as it is not the Rate Determining Step of the reaction. So although the observation is not wrong, its still not the deciding factor.

Source Link
Loading