Timeline for Rate of a reaction
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 2, 2018 at 19:04 | comment | added | Harshit Joshi | Yup I think that you are correct. I don't understand a thing. Thanks for the answer. | |
| Sep 2, 2018 at 19:00 | comment | added | orthocresol | You should look in a proper physical chemistry textbook, it can be somewhat involved. chemistry.stackexchange.com/a/42532/16683 is the standard proof but if you are new to the topic then you will find it to be lacking in detail. If you don't know what activities or chemical potentials are, or how they relate to $\Delta G$, then I suggest coming back to it at a later stage in your education. Or, of course, reading a physical chemistry textbook, which should explain all these concepts. | |
| Sep 2, 2018 at 18:33 | comment | added | Harshit Joshi | Sir, your comments lead to a lot many pages. Could you give me a link to the direct proof of the above expression. I don't have the Peter Rock's book. | |
| Sep 2, 2018 at 18:20 | comment | added | orthocresol | (1) Of course it will reach equilibrium. Everything does! (2) the equilibrium constant $K$ is still defined using stoichiometric coefficients. It is just that you can no longer derive it in that fashion, by saying that $K$ is a ratio of rate constants. There are other, more rigorous, ways of deriving it. This definition of the equilibrium constant using stoichiometric coefficients is necessary to fulfill all the other thermodynamic relationships, such as $\Delta G^\circ = -RT \ln K$, see e.g. my comments here. | |
| Sep 2, 2018 at 18:11 | comment | added | Harshit Joshi | We are actually taught equilibrium a year before kinetics. So will a non elementary multi step reaction never achieve equilibrium OR will we define the new $K_c as K_c = \frac{[C]^w[D]^x}{[A]^y[B]^z}$ where $w,x,y,z \neq$ stoichiometric coeffecients? | |
| Sep 2, 2018 at 17:56 | history | answered | orthocresol | CC BY-SA 4.0 |