When you move from level $n_1$ to level $n_2$, the total number of energy levels are $n_2-n_1+1$ (including $n_1$ and $n_2$). Now, you want to find the total number of possible spectral lines in the ...

As far as I have read, in general, exocyclic double bonds (which are outside the ring) are stable for 3 or 4 numbered rings while endocyclic double bonds (which are inside the ring) are stable in 5 or ...

If you check out the $\mathrm{p}K_\mathrm{a}$ values of paracetamol (acetaminophen) , it is 9.38 while $\mathrm pK_\mathrm a$ of para-methoxybenzene is 10.1. So, $\ce{-OR}$ should exert a greater ...

As @Waylander mentioned in comments, more information is needed to guess A and B. Since, in the question other products have not been mentioned, I am writing the answers for them with reasoning. 1) ...

For $b$, you have equivalent resonating structures as the structures are identical. The structures $a'$ and $b'$ are not correct as nitrogen cannot expand it's octet. For $a''$ and $b''$, the first ...

Note that under the given conditions, methanol cannot exist in the liquid state, however since you are given in the problem that methanol is obtained in liquid state, you will only consider the ...

So you need $$K_p = \frac{p_{\ce{H2S}}^3}{p_{\ce{H2}}^3}$$ where $p_{\ce{H2S}}$ and $p_{\ce{H2}}$ are partial pressures of $\ce{H2S}$ and $\ce{H2}$ respectively. Partial pressure is nothing but the ...

Yes, you are correct. For converting a nitrile to amide, we do controlled hydrolysis. So, first amide is obtained and then ammonium salt of the carboxylic acid is obtained. So, the reaction would be $$... View answer 2 votes You are indeed right, I confirmed that it is the fault in the diagram itself. See the diagram by wikipedia: View answer Accepted answer 1 votes As Ivan Neretin pointed out in the comments, \pi bonds will remain same whether or not in resonance. However, if you have trouble counting the double bond equvalent, you can directly use the formula ... View answer Accepted answer 1 votes We define a state function enthalpy as$$H=U+PV$$Since we cannot measure the absolute value of enthalpy, but the change in it, we modify the equation to$$\Delta H= \Delta U +\Delta(PV) Which is ...

Oxygen atom in the acetate ion is $\ce{sp^2}$ hybridized because as @Ivan Neretin said in comments, both the atoms are identical because the negative charge is in resonance with the $\pi$ bond of the ...

Specific heat capacity $\ce{C_p}$ can be used to calculate the enthalpy change even for the processes that are not at constant pressure as enthalpy is a state function, that is, it doesn't matter by ...