booma vijay
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Isomerization reaction involving carboxylic acid derivatives
5 votes

You need to understand something in organic chemistry. Not every question is going to be part of some named reaction that you just have to apply. For example in this question, the basic concepts of ...

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Bond rotation energy comparison of aromatic compounds
Accepted answer
1 votes

Cleavage of the double bond will lead to both compounds having two rings that are aromatic, however the amount of resonance energy(hence stability) will not be the same. Both systems will have a ...

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Acidic strength of diethyl malonate vs ethyl acetoacetate
1 votes

The hydrogens which you have chosen are correct but both the carbanions are NOT eqaully stablised via the resonance. In case of malonic ester, the elctrophilicity of the carbonyl(c=o) is reduced due ...

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Is this bond cleavage correct?
2 votes

The cleavage that you have shown is NOT favourable. The dipole of the carbon double bond O points towards the oxygen , not the carbon. The bond tends to shift onto the oxygen giving it a negative ...

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Reduction of only double bonds
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2 votes

You can do a normal hydrogenation reaction(H2,Pd) under low pressures as suggested by @Waylander. Alternatively you can use the Wilkinson's catalyst which also is a way to do catalytic hydrogenation ...

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Anti-Markovnikov addition of HCl
Accepted answer
5 votes

One way to do it would be do first do a hydroboration-oxidation reaction, which leads to the anti-Markovnikov addition of $\ce{H2O}$. So you will get an $\ce{-OH}$ group instead of $\ce{-Cl}$. Then, ...

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Addition to equally substituted carbons
Accepted answer
1 votes

The use of HBr with peroxide leads to an anti-Markonikov's product(known as the peroxide effect).The carbons are both substituted once, but not equally! One has a methyl group while the other side has ...

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Which compound will have the most stable enol form?
0 votes

In case of pholoroglucinol, its ketoform has 3 $\ce{C=O}$ bond which make its keto form more stable as compared to the keto form of 4-pyridone which has to offer only one $\ce{C=O}$.

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Specific reduction of certain functional groups
1 votes

1.The selective reduction of the carboxylic group is explained in this article. Link:https://www.ch.imperial.ac.uk/rzepa/blog/?p=5114. It could reduce esters but is not favourable at all and difficult....

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