user600016
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Chemical kinetics
7 votes

You have made an error in the final integration: $$\begin{align} t &= \int_{[\ce{A}]_0}^{[\ce{A}]_t}\frac{\mathrm d[\ce{A}]}{[\ce{A}]_0 - 2[\ce{A}]} \\ &= \frac{-1}{2} {\ln|{A_{0}-2[A]}|_{A_0}...

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My confusion regarding Hydrogen peroxide
Accepted answer
3 votes

Each oxygen atom is connected to a hydrogen atom(which develops -1 charge on oxygen and +1 on hydrogen) and to another $\textbf{oxygen}$ atom which contributes no charge to both(0 and 0). Similar for ...

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Markovnikov Rule of Alkenes
2 votes

My suggestion is to stop trying to predict the product by rules like “rich becomes richer” or “proton goes to carbon having greater number of hydrogens attached to it”, etc. for Markovnikov addition ...

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What happens when Hinsberg derivative is added to acidic solution?
2 votes

" compound produces a solid" indicates that a reaction has occured.(hence no 3° amine group(according to this)). Further this is insoluble in base so there is a 2° amine group. "This solid dissolves ...

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Celsius to Kelvin
2 votes

The point is, we are measuring $\textbf{change}$ in temperature. Not the temperature itself. Celsius scale has 100 divisions from 0 °C to 100 °C. Kelvin scale also has 100 divisions from 273 K to 373 ...

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Explain the structure of HNC (Hydrogen Isocyanide)
2 votes

In such type of questions, we can't directly determine Oxidation state by the normal algebra method. First you have to draw the structure. 1.In a covalent bond, the more electronegative element gets ...

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What happens when an alkyne reacts with ammoniacal Cu2Cl2?
1 votes

$$\ce{H-C#C-H ->[Cu2Cl2][NH4Cl] H-C#C- Cu+ }$$ This then attacks $\ce{H-C#C-H}$ to give $\ce{H-C#C-CH=CH2}$ Note: This occurs only for terminal alkynes and only in acidic medium(NH4Cl here). ...

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Most activated position for Electrophilic addition in substituted biphenyls
1 votes

Dipole moment is what matters in substituted biphenyls. The dipole moment in the first case is from left ring to right ring due to -OH groups predominant +M effect to the ring.(the alkene being an ...

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Why does reducing the pressure in an equilibrium reaction favour the side with more moles of gas?
Accepted answer
1 votes

For your reaction, $\Delta n_g = 3-(1+1)=1$ (assuming all A,B,C are gases). $K_p = \frac{[C]^3}{[A][B]} (\frac{P_{total}}{\Sigma n})^{\Delta n_g}$, where $\Sigma n$ is the total number of moles of ...

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Equilibrium Constant & Rate-Determining Step
1 votes

I will first try to answer your second question. There's absolutely no mistake you made! As you assumed first step is RDS(rate determining step), You would expect $K=K_{f1}$. Continuing from where ...

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SN1, SN2 and enantiomeric excess
1 votes

In this case, the absolute configuration remains same (as R) for $\mathrm{S_N1}$ and changes (into S) for $\mathrm{S_N2}.$ This is because the priority order of non substituted groups (wrt $\ce{C2})$ ...

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Friedel-Craft reaction with amide substituent
Accepted answer
1 votes

-NHCOCH3 is a slightly activating group due to the lone pair of N which shows +M effect. Hence it is Ortho para directing.

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Electroplating diamond grit
1 votes

Maybe these links would help: US3046204A - Method for making diamond tools - Google Patents https://patents.google.com › patent The Basics: Electroplating & Vacuum Brazing - Diamond ... https://...

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Balancing the Redox reaction by Half reactions
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0 votes

To make your problem simpler(equivalent of your problem) just balance this reaction: $\ce{I2 -> I^{-} + IO3^{-}}$ in basic medium. While balancing, the $\ce{OH-}$ on the LHS correspond to the ...

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How can I find the equilibrium constant Kp without temperature?
0 votes

$K_p=K_c(RT)^{\Delta n_g}$(try to prove this yourself) where $\Delta n_g$ is number of gaseous products -Number of gaseous reactants. In your question, $\Delta n_g=0$ so $K_p=K_c=2.43$

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Order of basicity
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0 votes

In aprotic or very small polar solvents like chlorobenzene, solvated ions cannot form so there is no solvent effect. It follows a 'similar' order as that in gaseous phase. Coming to the question, on ...

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Basicity of singlet and triplet carbene
0 votes

Singlet carbene is sp2 hybridised whereas triplet carbene is sp Hybridised. More s character, more nuclear force, more Electro negativity so more acidic hydrogen and hence less basicity. So singlet ...

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Reactions of alkynes with sodium/ammonia vs sodium amide
-1 votes

In the first case hydrogenation occurs(anti addition) whereas in the second case, acid base neutralization occurs. So they aren't identical. According to Wikipedia, $$\ce{2 Na + 2 NH3 -> 2 NaNH2 + ...

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Organic Chemistry - Reaction scheme and structures of molecules
-1 votes

Q is pentan-1-ol and not pentan-3-ol as on dehydration, of pental-1-ol, only one product (alkene) is formed. Whereas on dehydration of pentan-3-ol, we get two alkenes, as the alkene can show ...

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Which carbocation from following is stable by hyperconjugation?
Accepted answer
-1 votes

It should probably be option C as in one of its resonating structures, there is an alpha hydrogen(as it is saturated) wrt the carbocation formed. Hence, it can show hyper conjugation

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Stability order of Cr2+ ,Mn2+ , Fe2+ ,Co2+
Accepted answer
-1 votes

Formation of ion takes place by removing electron from outermost shell. Electronic configuration for Fe2+ is [Ar]3d6 4s0 Electronic configuration of Cr2+ is [Ar]3d4 4s0 Cr2+ is a stronger reducing ...

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