For the most part, coordination bonds involve d electrons from the transition metal interacting with some other electrons on a separate molecule. Hybrid orbitals are constructed from a single atom's ...

A more appropriate name for the ionic factor is the van't Hoff factor of colligative properties. In the simplest terms, it is the number of particles created after being dissolved in the solution. ...

When discussing hybrid orbitals, they are justified by the experimentally observed or calculated/simulated molecular geometry. For instance, the $\ce{^.C(CH3)3}$ radical was found to be planar by ab ...

In the simplest terms and most convenient definitions, the lowering of vapor pressure is not a colligative property while the relative lowering of vapor pressure is indeed a colligative property. A ...

There are a couple of ways to approach this problem. Bear in mind this problem requires some calculus. $\boldsymbol{1^{st}}$ Way (repeated integration): To start, you were able to recognize the first ...

In the simplest terms and most convenient definitions, it represents the total amount of states that the energy can be in. The probability expression you wrote emphasizes this. A probability is a ...

Graphene combusts at 620 K. See http://pubs.acs.org/doi/abs/10.1021/jp410044v. It is postulated that it burns at this temperature "because of a large interlayer spacing of graphene sheets (i.e., 5.1 ...

That is precisely the reason why. Zwitterions are defined as molecules that contain both a positive and a negative charge within the molecule. Alcohol groups won't deprotonate at neutral pH = 7. The ...

Yes, carbon-carbon bond rotation can happen in the open chain form of these carbohydrates. But you are confusing rotation with stereochemical configuration. This can only be altered by breaking bonds. ...

E-Z notation should be used here. But to answer your question, the longer chain off the double bond takes the priority. In this case, it is the ethyl group. So product 1 is trans while product 3 is ...

Did you mean to ask "what is the chemical formula of ammonium bisoxalatocuprate(II)", yes? If so, the compound is a salt and should be chargeless. $$\ce{(NH4)2[Cu(C2O4)]}$$ This is because oxalate is -...

Under $E_2$ reaction conditions, the MeO$^-$ product will be while the Me$_3$CO$^-$ product will be . This is due to the bulkiness of Me$_3$CO$^-$ being unable to reach the hydrogen at the ...

It is interesting to see you creating your own approach. The comments above provide good responses. I would recommend looking at Buttonwoods suggestion regarding collision theory and cross-sections. ...

This particular question is testing basic knowledge of buffers. In the most simplest explanation possible, a buffer will resist changes in pH the best when the pH is at the pKa. In the case of ...

This can be answered both conceptually and mathematically. Conceptually: Let's call the two reactions 1 and 2 with reaction 1 having the larger activation energy. Here is a plot of the arbitrary ...