# Tag Info

## New answers tagged transition-metals

0

Electronic configuration of $\ce{Fe}$ : $\mathrm{1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 3d^6 \ 4s^2}$ Add the electrons of 3rd shell $\mathrm{3s^2 + 3p^6 + 3d^6} = 14$ electrons And 4th shell $\mathrm{4s^2}$ contains $2$ electrons.

7

Dichlorobis(triphenylphosphine)nickel(II), or $\ce{NiCl2[P(C6H5)3]2}$ in square planar form is red and diamagnetic. The blue form is paramagnetic and features tetrahedral Ni(II) centers. Both tetrahedral and square planar isomers coexist in solutions. Weak field ligands, favor tetrahedral geometry and strong field ligands favor the square planar isomer. Both ...

11

We sometimes call this type of complex 'pseudotetrahedral' since there is an isomerism from a tetrahedral to a square planar complex possible. I was unable to find the original work here but this link gives some information. As you already mentioned there are two strong and two weak ligands so it's hard to tell how strong the ligand field splitting will be. ...

6

Pearson conveniently lists cumulative experimental data in the 1988 paper [1], referrring to the earlier work of Moore [2]. Selected values of $I$ (ionization potential), $A$ (electron affinity), $χ$ (absolute electronegativity – probably, that's what you are looking for) and $η$ (absolute hardness) for iron and cobalt cations are: Table I. Experimental ...

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