# Tag Info

1 vote

### Electrolysis when E_cell = 0

You are confused because you are mixing two different concepts. Half-cells belong to the field of potentiometry when no electric current is passing through the circuit. So that calculations you do ...
• 32.1k

### Displacement Reaction

User124053's explanation does not correspond to the reality. He or she says that "the more reactive metal essentially takes the place of the less reactive metal. But I can't seem to understand ...
• 20.8k
1 vote

### Displacement Reaction

This can be easily understood if one consider the electrochemical series. I can explain this concept with a simple and famous illustration. Consider the following reaction:  \ce{Zn + Cu^2+ -> Zn^...
• 1,180
1 vote

### Relative stability of $\ce{V^2+}$ and $\ce{V^3+}$ and their Standard Electrode Potential

An independent source gives $-0.37$ for titanium, $-0.26$ for vanadium and $-0.42$ for chromium, showing that vanadium is relatively high compared with its immediate neighbors. The book should have ...
• 38.3k
### Relative stability of $\ce{V^2+}$ and $\ce{V^3+}$ and their Standard Electrode Potential
The $\ce{E^°(M^3+/M^2+)}$ standard electrode potential for $\ce{V}$ has a low negative (that is, a relatively more positive) value. This is attributed to the greater stability of $\ce{V^2+}$ as given ...