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Group theoretical condition for an integral to be zero

I was not completely happy with any answer so far, so here is my take on this: We consider some integral $$ \int_{\Omega} f d\Omega $$ over some volume $\Omega$, ideally over $\mathbb{R}^d$, where $d$ ...
Trond Saue's user avatar
-2 votes

Why are excited Slater determinants used to describe electron correlation?

Actually there is a reason for this. The exact mathematical way to expand a function of N variables $\Psi(x1, x2...)$ - in terms of a basis - is a multi-determinant expansion, given the requirement ...
Mah Neh's user avatar
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