New answers tagged solid-state-chemistry
1
The mathematical answer is based on Clapeyron's equation (written in what follows in form inverted relative to the more usual):
$$\frac{dT}{dp}= \frac{\Delta V}{\Delta S}$$
which must hold on any point on the phase coexistence line.
If $\frac{dT}{dp}=0$ then it follows that $\Delta V=0$.
-1
in AlF3 in case of each AlF bond, charge of Al =3
=> product of charges in case of each bond=3
=>sum of products of charges =3x3=9>4
so, AlF3 has lattice energy more than MgO.
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