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The mathematical answer is based on Clapeyron's equation (written in what follows in form inverted relative to the more usual): $$\frac{dT}{dp}= \frac{\Delta V}{\Delta S}$$ which must hold on any point on the phase coexistence line. If $\frac{dT}{dp}=0$ then it follows that $\Delta V=0$.


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in AlF3 in case of each AlF bond, charge of Al =3 => product of charges in case of each bond=3 =>sum of products of charges =3x3=9>4 so, AlF3 has lattice energy more than MgO.


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