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4 votes

Why is the Molar mass of CO2 different than the weight of the sum of its particles?

This is a really interesting question actually! I'm new to answering questions on this site but I'll explain as best I can. As others have said, the difference in this particular calculation comes ...
cp95's user avatar
  • 101
3 votes

High School Chemistry Significant Figures

A rule of thumb is that the last significant figure in any stated answer should be of the same order of magnitude, i.e. in the same decimal position, as the uncertainty. For example, $$\displaystyle ...
porphyrin's user avatar
  • 30.8k
1 vote

Problem in finding relation between molarity and weight by weight percentage

$$\begin{align} \left(\frac{w}{W}\%\right) &= \frac{\text{wt. of solute}\ (w_\ce{A})}{\text{wt. of solution}\ (w)}\times100 \\ C_\ce{A} &= \frac{n_\ce{A}}{V_\text{solution}\ \ce{(in m\ell)}}\...
megamonster68's user avatar
1 vote

Problem in finding relation between molarity and weight by weight percentage

$$C_\mathrm{A}=\frac{n_\mathrm{A}}{V}=\frac{m_\mathrm{A}}{M_\mathrm{A}\;V}=\frac{\rho_\mathrm{A}}{M_\mathrm{A}}=\frac{y_\mathrm{A}\;\rho}{M_\mathrm{A}}$$ $$\frac{w}{w}\%=y_\mathrm{A}\cdot100\%$$ $$\...
Sam202's user avatar
  • 1,759
1 vote

Decomposition Redox Rxn Vs. Intramolecular Redox Rxn

Many decomposition redox reactions are not intramolecular redox reactions. Typical cases are radical chain reactions with catalytic effect of other minor compounds. Like the ozone decomposition, ...
Poutnik's user avatar
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1 vote

what really happens when an electron pair is shared in a bond?

When two atoms share an electron pair, does it mean the valence electrons of both atoms stop revolving in their shells and stop somewhere between the two atoms? Electrons in an individual atom move ...
SameerTahir's user avatar
1 vote

Air bag reaction calculation: gas volume and stoichiometry

Both of the answer keys are incorrect, it seems, and the OP's are correct. We can combine the two equations (in a way that no Na is left over) to make the calculations a bit easier: $$\ce{10 NaN3 + 2 ...
Karsten's user avatar
  • 41.2k

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