New answers tagged periodic-trends
-1
Always remember that cationic radii is always smaller than radii of parent atom whereas anionic radii is always larger than that of parent
Which gives us the conclusion that
$H^- > H >H^+$
The 2nd option is correct noble gases in a period have highest ionization energies and since fluorine is more electronegative than oxygen it has a higher ionization ...
2
Put very roughly, we can boil this down to why aluminum and sulfur are depressed with respect to the average of the surrounding elements.
Aluminum is $\ce{[Ne]{3}s^2{3}p^1}$. Its first ionization removes the $3p$ electron while leaving the more stable $3s$ orbital intact, whereas magnesium has to break its more stable $3s$ orbital. So by comparison, the ...
Top 50 recent answers are included
Related Tags
periodic-trends × 295inorganic-chemistry × 91
periodic-table × 72
ionization-energy × 29
transition-metals × 23
atomic-radius × 23
electronegativity × 17
bond × 16
electron-affinity × 16
electronic-configuration × 15
physical-chemistry × 14
melting-point × 13
halides × 12
atoms × 12
elements × 11
ions × 10
boiling-point × 10
oxidation-state × 9
electrons × 8
metal × 8
acid-base × 7
solubility × 7
reactivity × 7
organic-chemistry × 6
redox × 6