New answers tagged nmr-spectroscopy
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I agree with Buck Thorn's comment. I suspect the coupling in the quartet is just not fully resolved. I'm not 100% sure why, but one possible reason is because there is further unresolved coupling with the OH peak: instead of being resolved as a splitting in the spectrum this just broadens the individual lines. Or it could just be that that proton relaxes ...
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There are atom nuclei with a non-zero magnetic spin, for example $\ce{^1H}$ (the most frequently seen isotope of hydrogen), but not $\ce{^2H}$ (deuterium). You may think about these atoms like small magnets. The orientation of these little magnets in space does not matter until these are brought into a strong magnetic field of the NMR spectrometer; here, ...
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When a radiation like the light is sent on some colored substance, part of the light goes through, and the other radiation (other colors) are absorbed. The energy of the absorbed radiation is used to push orbital electrons to a more excited orbital, may be at a greater distance from the nucleus.
The visible light is characterized by a wave length situated ...
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Although the nitrogen atom is more electronegative than carbon, nitrogen will readily share its electron pair, allowing one to draw a resonance structure where the nitrogen is donating electron density into the ring. Therefore, the donating of the lone pair of electrons overcomes the inductive effects arising from the difference in electronegativity.
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