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Sodium fluoride may react with small amounts of insoluble compounds like silica $\ce{SiO2}$ or silicates present in glass. It will produce some fluorosilicates which are soluble in water, according to the global equation : $$\ce{SiO2 + 6 NaF + 4 NaHSO4 -> Na2SiF6 + 4 Na2SO4 + 2 H2O}$$ Matter of fact, this reaction is the sum of two intermediate ...


Comparing the conductivities must start with some data - then you start dealing with explanations. Otherwise, you are making predictions - no, not predictions - speculations. Get some data first, then compare, speculate, hypothesize, predict, check predictions, repeat. As far as electrical conductivities, tables exist (

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