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Although the comment by Ezze is a valid and helpful answer, according to chegg.com, the order of reaction with respect to the $\ce{H+}$ ion is $\ce{0}$ and therefore it can be omitted from the rate expression as $\ce{[H+]^0= 1}$.


I tried to find the place where you found the two statements, and I could not. Absence of long-range forces The first statement makes sense to me: There are no intermolecular forces except during the collision between molecules. The OpenStax Chemistry textbook, for example, has this statement: Gases are composed of molecules that are in continuous ...


It appears that you are correct in your thought process. Determining by how much the activation energy of the reaction is reduced requires you to basically find $$Δ(\%) = \frac{E_\mathrm{a1} - E_\mathrm{a2}}{E_\mathrm{a1}} × 100\% = \left(1 - \frac{E_\mathrm{a2}}{E_\mathrm{a1}}\right) × 100\%$$ There is a system of three independent equations $$ \begin{...

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