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Bassam Shakhashiri's book entitled "Chemical Demonstrations, A Handbook for Teachers of Chemistry" gives a detailed study of the mechanism of the blue bottle, in his Volume $2$, page $145$ ($... 7 votes ### Mechanism of the blue bottle experiment According to Shakhashiri and coworker's 2012 J. Chem. Ed. paper, the linear form of glucose forms an endiolate which gets oxidized to a dicarbonyl (on carbon 1 and 2) and then further reacts with the ... 6 votes Accepted ### Negative or fractional order of reaction Wikipedia has you covered for both parts of the question in their article on Rate equation. They give an example of a negative order of reaction: $$\ce{2 O3(g) -> 3 O2(g)}$$ Under certain ... 3 votes ### Half-life of a reversible first-order reaction of the form A ⇄ B In the reaction$A\rightleftharpoons B$the relaxation rate constant, i.e. the rate of approach to equilibrium is exponential and given by$k=k_1+k_{-1}$. The forwards and reverse reactions have rate ... 3 votes Accepted ### Half-life of a reversible first-order reaction of the form A ⇄ B The Wikipedia article on half-life states: The term "half-life" is almost exclusively used for decay processes that are exponential (such as radioactive decay or the other examples above), ... 3 votes Accepted ### Required induction time for steady-state approximation to hold Let's look at your exact solution again. $$[\mathrm{B}] = \dfrac{k_1[\mathrm{A}]_0}{k_2-k_1} \left( e^{-k_1\ t} - e^{-k_2\ t} \right) \qquad$$ Let's think carefully about the criteria for the ... 3 votes ### Serial reactions or consecutive reactions: rate vs time Simple anwser. Your answer is correct. The concentration of species B reach a maximum when the rate of formation of the intermediate must equals the rate of dissapeance. Since$r_B$can be written as$...
You are right that you can determine the backwards rate if you know the forward rate and the equilibrium constant. In fact, you have the right formula $$K_c = \frac{k^f}{k^b}$$ In general, the ...
In principle, the pyrolysis of $\ce{CaCO3}$ is an equilibrium, which should be described with a double arrow. But usually this equation is considered as not reversible, because $\ce{CO2}$ does not ...