7
votes
Mechanism of the blue bottle experiment
Bassam Shakhashiri's book entitled "Chemical Demonstrations, A Handbook for Teachers of Chemistry" gives a detailed study of the mechanism of the blue bottle, in his Volume $2$, page $145$ ($...
- 21.8k
7
votes
Mechanism of the blue bottle experiment
According to Shakhashiri and coworker's 2012 J. Chem. Ed. paper, the linear form of glucose forms an endiolate which gets oxidized to a dicarbonyl (on carbon 1 and 2) and then further reacts with the ...
- 30.9k
6
votes
Accepted
Negative or fractional order of reaction
Wikipedia has you covered for both parts of the question in their article on Rate equation.
They give an example of a negative order of reaction:
$$\ce{2 O3(g) -> 3 O2(g)}$$
Under certain ...
- 30.9k
3
votes
Half-life of a reversible first-order reaction of the form A ⇄ B
In the reaction $A\rightleftharpoons B$ the relaxation rate constant, i.e. the rate of approach to equilibrium is exponential and given by $k=k_1+k_{-1}$. The forwards and reverse reactions have rate ...
- 27.1k
3
votes
Accepted
Half-life of a reversible first-order reaction of the form A ⇄ B
The Wikipedia article on half-life states:
The term "half-life" is almost exclusively used for decay processes that are exponential (such as radioactive decay or the other examples above), ...
- 30.9k
3
votes
Accepted
Required induction time for steady-state approximation to hold
Let's look at your exact solution again.
$$
[\mathrm{B}] = \dfrac{k_1[\mathrm{A}]_0}{k_2-k_1} \left( e^{-k_1\ t} - e^{-k_2\ t} \right) \qquad
$$
Let's think carefully about the criteria for the ...
- 20.3k
3
votes
Serial reactions or consecutive reactions: rate vs time
Simple anwser.
Your answer is correct. The concentration of species B reach a maximum when the rate of formation of the intermediate must equals the rate of dissapeance.
Since $r_B$ can be written as
$...
- 618
2
votes
How to compute backward reaction rate from forward one and an equilibrium data
You are right that you can determine the backwards rate if you know the forward rate and the equilibrium constant. In fact, you have the right formula
$$ K_c = \frac{k^f}{k^b} $$
In general, the ...
- 126
2
votes
Rate law for thermolysis at temperatures well above the decomposition temperature
In principle, the pyrolysis of $\ce{CaCO3}$ is an equilibrium, which should be described with a double arrow. But usually this equation is considered as not reversible, because $\ce{CO2}$ does not ...
- 21.8k
Only top scored, non community-wiki answers of a minimum length are eligible