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It seems this name should not be in the blue book. It is an error.
The following instruction is what Corrections to Nomenclature of Organic Chemistry. IUPAC Recommendations and Preferred Names 2013 has given for your problem:
Page 82, P-15.3.2.4.1, example 4 on this page.
Delete 1,1′-(2-ethenyl-1,2,3-trimethyldisilazane-1,3-diyl)bis(ethan-1-one).
As ...
5
(I will simply be converting my comments above into an answer here)
Yes, generally, you can apply this in cases with similar geometry. You can see why from the following rationale:
Imagine that the bond pairs look like a ring-shaped cloud, and one is worn on your index finger and another on your middle finger, both towards the fingertip. For example, to ...
3
I know nothing about drilling mud.
Solutions of both $\ce{Na2CO3}$ and $\ce{K2CO3}$ will precipitate calcium carbonate.
$$\ce{Na2CO3 ->[H2O] 2Na+(aq) + CO3^{2-}(aq)}$$
$$\ce{K2CO3 ->[H2O] 2K+(aq) + CO3^{2-}(aq)}$$
$$\ce{Ca^{2+}(aq) + CO3^{2-}(aq) <=>[H2O] CaCO3 v}$$
Since there is already some $\ce{KCl}$ in solution this would slightly ...
2
If the reaction happens at neutral or mildly alkalic $\mathrm{pH}$:
$$\ce{6I- + 4 H2O + 2 MnO4- -> 3 I2 + 2 MnO2 (s) + 8 OH-}$$
If the reaction happens at mildly aciding $\mathrm{pH}$, it could be as well:
$$\ce{6I- + 8 H+ + 2 MnO4- -> 3 I2 + 2 MnO2 (s) + 4 H2O }$$
In any case, either spending $\ce{H+}$ either production $\ce{OH-}$ increases $\...
2
Yes, there are numerous known lead(II) o-phenanthroline complexes with thiocyanate, perchlorate and bulkier organic ligands.
As for nitrate, Bytheway et al. [1] reported synthesis (from lead(II) nitrate in methanol) and crystal structure of bis((1,10-phenanthroline)-(nitrato-O,O'))-lead(II):
Figure 1. crystal structure of $\ce{[(phen)2Pb(NO3)2]}$ (CCDC: ...
2
What you are missing is understanding of general nature of redox reactions. Redox reactions need two half reactions to complete. You can't arbitrarily select these two half reactions. They has to be chosen as instructions given in the problem. For example, for your given problem, it should be noted the medium of the reaction, whether it is acidic or basic or ...
1
There are several electronegativity scales. In the Pauling scale, H and P are at 2.1. In the Mulliken scale, H is at 2.2 and P at 2.3. In the Allred and Rochow scale, it is the contrary : H is at 2.2 and P at 2.1. These scales are contradictory for H and P. So it is necessary to choose for teaching purposes. And book authors have usually chosen +1 for H, ...
1
For the reaction:
$$\ce{6I- (aq) + 4 H2O + 2 MnO4- (aq) ->[excess I-] 3 I3- + 2 MnO2 (s) + 8OH-}$$
what you are missing is the Nernst Equation. The two reduction half cell reactions are:
$$\ce{I3− + 2e- <=> 3I− \quad\quad EMF = +0.53}$$
$$\ce{MnO4− + 2H2O + 3e− <=> MnO2(s) + 4 OH− \quad\quad EMF =+0.595}$$
The gist of the Nernst ...
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Russian interstate standard GOST 18293-72 "Drinking water. Methods for determination of lead, zinc and silver content" (PDF in Russian) suggests to use sulfarsazene (plumbone), which forms orange-yellow complex with lead(II).
Reported method sensitivity (spectrophotometry): $\pu{0.5 μg L-1}.$
A brief review in English [1, p. 315]:
To determine lead in ...
1
In phosphorus trihalides backbonding effect is not as big as boron trihalides. Firstly boron trihalides are trigonal planar and have an empty-and-small p orbital (violates the octet rule), so it is favourable that the p orbitals of the boron and the halogen atom will overlap; meanwhile phosphorus trihalides are trigonal pyramidal which is less favourable for ...
1
In my opinion the difference in charge always prevail over atomic radius. Additionally, according to the Born-Lande equation says the lattice energy is proportional to the charges on each ion, not the charge difference. The fluoride ion has a 1- charge which is smaller than the nitride which is 3-.
Anyways these ionic solids have different structures and ...
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