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3

You kind of had the right idea, but not quite. First of all, they gave you the molar heat capacity at constant pressure, so you didn't have to express it in terms of the degrees of freedom. Secondly, the change in entropy is not Q/T, it is $\int{\frac{dQ_{rev}}{T}}$. Third, for a constant pressure process, $dH=dQ=nC_pdT$ This should be enough information to ...


2

Since the temperature of the solid is now slightly lower than the temperature of the surrounding water, heat will be transferred from the water to the solid until the temperatures are equal It is fine to think that way as a rough draft in rationalizing this process. The only issue is that temperature is a macroscopic quantity, and mechanism tends to be a ...


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