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Tin chloride $\ce{SnCl2}$ (hydrated or not) is not soluble in pure water. It is quickly hydrolyzed according to : $$\ce{SnCl2 + 2 H2O -> Sn(OH)2 + 2 HCl}$$ and $\ce{Sn(OH)2}$ is insoluble in water. To dissolve $\ce{SnCl2}$, this reaction has to be reversed by adding $\ce{HCl}$ in $5$ M solution. In this case, a clear solution is obtained. Unfortunately $\...


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