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The mass of copper deposited on the cathode does not depend on the molarity of the solution. It depends only on the intensity of the current and of the duration the electrolysis.


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You don't get a precipitate if you add coppper(II) sulfate to hot salicylic acid. It becomes a clear dark green liquid. I assume the low pH because of the addition of the sulfate ion causes the formation of an acidic complex. I added some bicarb and the copper salicylate formed a light green powder. I added enough till it stopped effervescing as I don't have ...


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Required energy $E$ can be found as a product between voltage $U,$ current $I$ and time $t$: $$E = UIt\label{eqn:1}\tag{1}$$ Unknown multiplier $It$ can be found using united Faraday law: $$m = \frac{MIt}{zF}\quad\implies\quad It = \frac{mzF}{M}\label{eqn:2}\tag{2}$$ where $m$ is the mass of the substance liberated at the electrode; $M$ is the molar mass;...


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