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1

The article text itself does go into details. The first thing to note: while aromaticity on the larger scale is retained in your structures 3 and 4, this is only true for the 10-π-electron system as a whole. In many of these types of 10 π systems made up of a six-membered and a five-membered ring, the two rings are not equal with the double bond ...

0

In the hexagonal closest-packed structure, $a = b = 2r$ and $c = 4 \sqrt{\frac23 }r$, where $r$ is the atomic radius of the atom. The sides of the unit cell are perpendicular to the base, thus $\alpha = \beta = 90^\circ$. For a closest-packed structure, the atoms at the corners of base of the unit cell are in contact, thus $a = b = 2 r$. The height ($c$) of ...

4

Rather $$\ce{2 NaOH(aq) + CO2(g) -> Na2CO3 (aq) + H2O}$$ and analogically on the solid $\ce{NaOH}$. Bicarbonate in aqueous solutions cannot survive the excess of hydroxide, forming carbonate. $$\ce{HCO3^{-}\ (aq) + OH- (aq)<=>> CO3^{2-}(aq) + H2O}$$ The same is further enforced by dehydration effect of solid hydroxide. \ce{NaHCO3(s) + ...

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