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Find the pH of a solution obtained by mixing 100 ml 0.1m Na3PO4 and 100 ml 0.1 M NaH2PO4. Given that H3PO4: [Κα₁ = 10^-4, Κα₂ = 10^-7, Каз = 10^-11]

Your solution is simply a $0.1$ M solution of $\ce{Na2HPO4}$. And its pH is the average value of $p\pu{\mathrm{K}_{a2}}$ and $p\pu{\mathrm{K}_{a3}}$, which is $\frac{7+11}{2} = 9$.
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