New answers tagged

2

The excess of $\ce{O2}$ is ${7.32~ mol}$. So the excess air is : ${7.32 ~mol· (1 + 3.76) = 34.84~ mol}$. The total amount of air is : ${a·4.76 = 19.53~ mol ·4.76 = 92.96~ mol}$. The percentage of excess air is : $34.84/92.96 = 0.3748 = 37.48$%


0

It really depends exactly on what you're mixing the water with. Soaking a rag or paper towel will reduce the flammability and is recommended by many safety organizations online (here is one). However, if you are washing off a large amount of solvents or flammables with water and the chemicals are immiscible in water, it can sit on the top of the water and ...


Top 50 recent answers are included