New answers tagged aromatic-compounds
0
You can take both factors (1) and (2) combined as the reasoning for the greater acidicity of the former.
When you are comparing stability(in thermodynamic terms) of two conjugate bases, you are basically trying to position them with respect to each other on the energy axis of the energy profile (or reaction coordinate diagram)
In this case, the reaction ...
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There's almost nothing you can do in this situation, unfortunately. Because of strong coupling and other issues, aromatic peaks often do not conform to the so-called $n+1$ rule, which makes it highly non-trivial to extract coupling constants. It is probably possible to "fit" coupling constants to the multiplet shape by simulating the spectrum for a given set ...
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The product you are suggesting is very unstable as compared to the ones given as answers due to steric factors. Thus it would not be formed.
Since −OH and −CH3 are o,p-directing groups, shouldn’t the major product be 3-methyl-2-nitrophenol? Why not?
The reasoning that hydroxyl and methyl are o,p directing groups is not at supportive as to why 3-methyl-2-...
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TL;DR: It's 2 (2,2'‐dibromo‐6,6'‐diiodo‐1,1'‐biphenyl) and maybe even 3 (2,2'‐diiodo‐1,1'‐biphenyl; 2,6‐dimethyl‐1,1'‐biphenyl) at higher temperatures.
Introduction
According to the IUPAC gold book chirality is defined the as the geometric property of a rigid object of being non-superposable on its mirror image. Orr in other words, such an object has ...
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