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3

During neutralization of the buffer by a strong base solution, there are ongoing three reversible reactions, maintaining three equilibria: \begin{align} \ce{H2O + A- &<=> OH- + HA} &\quad K_\mathrm{b} &= \frac{\ce{[OH-][HA]}}{\ce{[A-]}} \tag{1}\\ \ce{H2O &<=> OH- + H+} &\quad K_\mathrm{w} &= \ce{[H+][OH-]} \tag{2}\\ \... 3 First of all you made a slight mistake one of the equations is wrong First equilibrium reaction,\ce{Ag(aq)+ + e- <=> Ag(s)}$$Writing the Nernst equation for this reaction$$\ce{E_{Ag|Ag^+} = E_{Ag|Ag^+}^0 - \frac{RT}{F}ln\frac{\ce{[Ag]}}{\ce[Ag^+]}}$$Second equilibrium reaction,$$\ce{AgCl(s) + e- <=> Ag(s) + Cl-(aq)} Writing the Nernst ...

3

OP's question is: Is the conductivity of $\ce{CaSO4}$ the difference of $\pu{7.0 \times 10^{−4} S cm−1}$ and $\pu{2.6 \times 10^{−4} S cm−1}$? In this question, $\pu{2.6 \times 10^{−4} S cm−1}$ is the conductivity of original aqueous $\ce{Na2SO4}$ solution and $\pu{7.0 \times 10^{−4} S cm−1}$ is the conductivity of original aqueous solution when saturated ...

1

The available literature is conflicting. On the one hand, a website claims that its SAP is unsatisfactory for absorbing ammonia, acetone and isopropanol (Ref 1). On the other hand, there is a patent that claims an SAP polymer specifically for absorbing ammonia (Ref 2). The monomers that are used to make the super absorbent polymer may be sodium or ammonium ...

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