3

During neutralization of the buffer by a strong base solution, there are ongoing three reversible reactions, maintaining three equilibria: $$ \begin{align} \ce{H2O + A- &<=> OH- + HA} &\quad K_\mathrm{b} &= \frac{\ce{[OH-][HA]}}{\ce{[A-]}} \tag{1}\\ \ce{H2O &<=> OH- + H+} &\quad K_\mathrm{w} &= \ce{[H+][OH-]} \tag{2}\\ \...


3

First of all you made a slight mistake one of the equations is wrong First equilibrium reaction, $$\ce{Ag(aq)+ + e- <=> Ag(s)}$$ Writing the Nernst equation for this reaction $$\ce{E_{Ag|Ag^+} = E_{Ag|Ag^+}^0 - \frac{RT}{F}ln\frac{\ce{[Ag]}}{\ce[Ag^+]}}$$ Second equilibrium reaction, $$\ce{AgCl(s) + e- <=> Ag(s) + Cl-(aq)}$$ Writing the Nernst ...


3

OP's question is: Is the conductivity of $\ce{CaSO4}$ the difference of $\pu{7.0 \times 10^{−4} S cm−1}$ and $\pu{2.6 \times 10^{−4} S cm−1}$? In this question, $\pu{2.6 \times 10^{−4} S cm−1}$ is the conductivity of original aqueous $\ce{Na2SO4}$ solution and $\pu{7.0 \times 10^{−4} S cm−1}$ is the conductivity of original aqueous solution when saturated ...


1

The available literature is conflicting. On the one hand, a website claims that its SAP is unsatisfactory for absorbing ammonia, acetone and isopropanol (Ref 1). On the other hand, there is a patent that claims an SAP polymer specifically for absorbing ammonia (Ref 2). The monomers that are used to make the super absorbent polymer may be sodium or ammonium ...


Only top voted, non community-wiki answers of a minimum length are eligible