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It's true that tertiary alcohols cannot react with PX3 where X is a halogen (usually Cl or Br). The reason lies in the mechanism. The attack of X- on the protonated alcohol is Sn² which is not possible on 3° carbon. PS : Refer to the mechanism attached!


If you leave it to E1, you will not get the selectivity you need. The difference between the methyl group and the methylene unit is steric bulk. You can select for deprotonation of the methyl for elimination via a bulkier base in an E2 reaction. In addition, you will need to convert the substrate so that it has a good leaving group. For an alcohol, this is ...


I found this answer for IV And in V-B is formed because it is more conjugated


When you are using Grignard reagent for opening of epoxides, the Grignard reagent will attack less sterically hindered carbon(i.e. SN2 attack will take place). This is because when we use Grignard reagent, the reaction takes place in basic medium. Therefore in step 3 it will attack the 1st carbon instead of the 2nd one.


Yes, I think that lower alcohols cannot be dried using $\ce{CaCl2}$ as they form stable complexes with it but higher alcohols can be dried using $\ce{CaCl2}$ as they form unstable complexes while water forms stable complex. On the other hand, aromatic alcohols like phenols can't be dried using $\ce{CaCl2}$ as they are somewhat acidic in nature. At the same ...

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