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Inorganic compounds generally do not have C-H bonds, while organic compounds do have such bonds. The distinction between inorganic and organic chemistry, however, is far from absolute.

7
votes
I believe that magnesium exposed to air quickly ends up with a coating of magnesium oxide on its surface. This oxide coating is quite uniform and does not allow any further oxygen to reach the surfac …
answered Nov 24 '12 by Paul J. Gans
4
votes
Sodium hypochlorite, $\ce{NaClO}$, is unstable and can't be separated from the water in which you usually find it without it decomposing. That's the short answer. To learn more about it check Wikipe …
answered Oct 8 '12 by Paul J. Gans
5
votes
The chemicals must be in water, since magnesium bicarbonate decomposes when dried. So I will assume that the mixing is done in water. To start with, both salts are strong electrolytes and so they imm …
answered Feb 3 '13 by Paul J. Gans
4
votes
Another way of looking at this is to understand that the structure is always $$\ce{M-O-H}$$ where $\ce{M}$ is the metal atom. If the $\ce{O-H}$ bond is weaker than the $\ce{M-O}$ bond, the material …
answered Sep 26 '12 by Paul J. Gans
4
votes
The general answer to this question is no, one cannot simply predict the products of any reaction. How do we know that one of the products is not $\ce{S2O6^{2-}}$ or perhaps even $\ce{S2O5Cl2^{2-}}$? …
answered Dec 5 '12 by Paul J. Gans
2
votes
I think that there is no really good classical reason. Heat conductivity in a solid depends on bonding in that solid and bonding is inherently a quantum mechanical phenomenon. For instance, recall t …
answered Dec 22 '12 by Paul J. Gans
8
votes
I believe that gaseous ionic compounds such as NaCl are in fact diatomic NaCl. One can't create a plasma by simply boiling ordinary compounds. The forces between ions are way too strong.
answered Nov 7 '12 by Paul J. Gans
3
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In the end there is no way to predict the structure of a given molecule. Yes, with experience one can guess correctly in many cases, but not in all of them. The way all this works is to first find t …
answered Jan 12 '13 by Paul J. Gans