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Redox is the portmanteau of reduction and oxidation. This tag should be used in questions where both the reduction and the oxidation process are under focus. This tag is not limited to inorganic chemistry. If the question is specifically about either reduction or oxidation (not both) of an organic compound, use [organic-reduction] or [organic-oxidation] instead.

3
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As you told oxidation number(oxidation state) is number assigned to atom, ion or compound which represent electron gain or lost by atom, ion or compound. Some element have more than one oxidation num …
answered Sep 22 '14 by Freddy
4
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oxidation half reaction, gives finally balanced redox reaction: $$\ce{CuS + 3SO4^{2-} + 6H+ -> 4SO2 +CuO + 3H2O}$$ (Thanks to Silvio Levy for helping me to solve this problem.) …
answered Jul 22 '14 by Freddy
2
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redox reaction: The reaction in which oxidation and reduction occurs simentationesly is called redox reaction There are mainly three different ways of determining oxidation and reduction reaction … . Electron transfer method [method which you mentioned.] Oxidation State method [Highly used] Increase in oxidation state is called oxidation. Decrease in oxidation state is called reduction. redox
answered Sep 14 '14 by Freddy
5
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1answer
Balance the following reaction: $$\ce{CuS + SO4^{2-} -> CuO + SO2}$$ Below, the number mentioned in the parenthesis is the oxidation number of sulfur. I have found out that the oxidation half-r …
asked Jul 22 '14 by Freddy
5
votes
1answer
I have got the homework to balance the following redox reaction. $\ce{Cr(OH)3- + HO2- -> Cr2O7^{-2} + OH- }$(Basic medium) To balance this reaction first thing we need to do is to find the …
asked Jul 18 '14 by Freddy
1
vote
Balancing With Half Reaction method Step 1: Determine oxidation number of each element. $$\ce{Fe^{(2)}S2^{(-1)} + O2^{(0)} -> Fe2^{(3)}O3^{(-2)} + S^{(4)}O2^{(-2)} }$$ Step 2: Determine tot …
answered Sep 23 '14 by Freddy
2
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2answers
Question: Balance the following redox reaction: $$\ce{FeS2 + O2 -> Fe2O3 + SO2}$$ My Efforts: I tried balancing with oxidation number method. First of all i determined the oxidation state …
asked Sep 22 '14 by Freddy