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This tag is for questions concerning coordination compounds including but not limited to ligand properties, metal properties, orbital splitting, micro- and macroscopic properties of entire complexes etc. For complexes where carbon monoxide is the only ligand, use [tag:carbonyl-complexes] instead. For organic catalysts or proteins, the tag is applicable if the question is about the metal’s direct coordination sphere.

2
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In reality it would perhaps boil down to experimental reasoning, but if it's an exam asking you this, I'd like you to remember a rule of thumb as you'd call it: If the complex has a coordination num …
answered May 23 '17 by Berry Holmes
2
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Please allow me to answer the question in two parts. Stability of carbonates We observe this order when we compare the thermal stability of group I-A carbonates: $$\ce{Li2CO3 \lt Na2CO3 \lt K2CO3 \l …
answered Apr 22 '17 by Berry Holmes
6
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There's a certain amount of misinformation here: sulfate is a bidentate ligand Sulfate is actually a flexidentate ligand, which is a term used to describe a polydentate ligand which is found to …
answered May 16 '17 by Berry Holmes
9
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Ethylenediammine or $en$ is an symmetrical didentate ligand. You can remember a rule of thumb for this if you like: In the case of $3$ symmetrical didentate ligands, i.e. $[\ce{M(AA)3}]$, the comp …
answered May 24 '17 by Berry Holmes
4
votes
I would like to add an answer stating a few exceptions which would come handy to you in future: $\ce{Ni^{2+}}$ has a $3d^8$ configuration. In this case strong field ligands ($\ce{C}$ or $\ce{N}$ do …
answered Apr 17 '17 by Berry Holmes
6
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It's quite elementary (perhaps). Silver (and gold) are known to show two main coordination numbers in its compounds, namely, $2$ and $4$. To start, we can consider $\ce{[Ag(OH)2]-}$ to be our initial …
answered Apr 27 '17 by Berry Holmes
3
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If you calculate the oxidation state of the central metal atom in both of these cases, you'll find it to be $+3$. With $\ce{Co^3+}$, all ligands behave as strong field ligands except in the cases of $ …
answered Apr 21 '17 by Berry Holmes
6
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An attempt to simplify (to make it a bit more comprehensible to a curious highschooler) and explain some of the terminologies used in Xahoc's answer. This is not intended to be a standalone answer and …
answered May 18 '17 by Berry Holmes