# Search Results

Results tagged with Search options answers only user 418
5 results

The mole is a standard amount of a substance A mole of a substance is a number of units (particles, atoms, molecules, ions, peas, hard candies, people, universes) equal to the number of atoms of carbon-12 in one gram of carbon-12, or an Avogadro's number of stuff. The mole allows us to relate real-word measurements to atomic scale phenomena.

]$= 10.0M In equilibrium,$[AB]$= 8.0M For every mole of$B$, one mole of$AB$is produced. For every mole of$A_2$, two moles of$AB$are produced. With just one cup of coffee so far, I get $$K_c = \frac{8^2}{(8 - \frac{8}{2})(10-8)^2} = 4$$ … answered Jan 4 '14 by Klaus-Dieter Warzecha$\ce{S6}$,$\ce{S8}$,$\ce{S12}$– does it make a difference or is it just a trick to make the question more complicated than it is? What you know for sure is:$M(\ce{S}) = 32.065\ \mathrm{g}\cdot …
answered Apr 16 '15 by Klaus-Dieter Warzecha
Did you calculate the volume using $V = \frac{4}{3} \cdot 3 \cdot (5 \cdot 10^{-7}\;m)^3\,$? Then your volume is in $m^3$, not in liter.
answered Jan 18 '14 by Klaus-Dieter Warzecha
For the elements A and B, the relation between the number of atoms n, the mass m, and the atomic mass M is given by Your assignment states: $$m_B = 2\cdot m_A$$ $$M_B = 2\cdot M_A$$ Solve for $n … answered Mar 11 '16 by Klaus-Dieter Warzecha I'm stuck, because both of them are having two moles of each of the respective molecules. Sure?$M(\ce{H2O}) = 18\,\mathrm{g\,mol^{-1}}M(\ce{N2O5}) = 108\,\mathrm{g\,mol^{-1}}\$
answered May 16 '15 by Klaus-Dieter Warzecha