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The mole is a standard amount of a substance A mole of a substance is a number of units (particles, atoms, molecules, ions, peas, hard candies, people, universes) equal to the number of atoms of carbon-12 in one gram of carbon-12, or an Avogadro's number of stuff. The mole allows us to relate real-word measurements to atomic scale phenomena.

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]$ = 10.0M In equilibrium, $[AB]$ = 8.0M For every mole of $B$, one mole of $AB$ is produced. For every mole of $A_2$, two moles of $AB$ are produced. With just one cup of coffee so far, I get $$ K_c = \frac{8^2}{(8 - \frac{8}{2})(10-8)^2} = 4$$ …
answered Jan 4 '14 by Klaus-Dieter Warzecha
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$\ce{S6}$, $\ce{S8}$, $\ce{S12}$ – does it make a difference or is it just a trick to make the question more complicated than it is? What you know for sure is: $M(\ce{S}) = 32.065\ \mathrm{g}\cdot …
answered Apr 16 '15 by Klaus-Dieter Warzecha
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Did you calculate the volume using $V = \frac{4}{3} \cdot 3 \cdot (5 \cdot 10^{-7}\;m)^3\,$? Then your volume is in $m^3$, not in liter.
answered Jan 18 '14 by Klaus-Dieter Warzecha
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For the elements A and B, the relation between the number of atoms n, the mass m, and the atomic mass M is given by Your assignment states: $$m_B = 2\cdot m_A $$ $$M_B = 2\cdot M_A $$ Solve for $n …
answered Mar 11 '16 by Klaus-Dieter Warzecha
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I'm stuck, because both of them are having two moles of each of the respective molecules. Sure? $M(\ce{H2O}) = 18\,\mathrm{g\,mol^{-1}}$ $M(\ce{N2O5}) = 108\,\mathrm{g\,mol^{-1}}$
answered May 16 '15 by Klaus-Dieter Warzecha