When carbon-14 decays, the decay products are nitrogen-14 and an electron (<strike>and an electron antineutrino, but that's chemically irrelevant</strike>*):

$$\ce{^14_6C -> ^14_7N + e- + \overline{v_e}}$$

Let's assume that the carbon atom in question is part of a carbon dioxide molecule in the atmosphere. What would happen to the molecule when the atom decays into nitrogen? Will it be converted into a $\ce{NO2}$ molecule, or will it split apart? Will the electron created in the decay have sufficient energy to escape the molecule and form a positive ion?

[Here](https://chemistry.stackexchange.com/questions/39458/curious-about-the-chemistry-of-carbon-14-after-its-produced-in-the-atmosphere)'s a somewhat related question dealing with the formation of radioactive carbon dioxide.

\* Of course, not all the energy from the defect will be transferred to the beta particle's kinetic energy, so this is in fact relevant for the rate. See Loong's answer for details.