[![enter image description here][1]][1]


  [1]: https://i.sstatic.net/0LFGi.png

I figured that the first reaction just adds a bromine to the meta position but I don't know what step ii) does. The only thing I can think of is the base gets rid of the alpha hydrogen next to the carbonyl. Then perhaps the negative carbon now attacks iodine? But that seems a bit off to me.