1. Calculate your **DBEs** (double bond equivalents):


\\[\mathrm{DBE} = \frac{2c-h+2}{2} = \frac{2\cdot 11 - 14 +2}{2} = 5\\] 
Note that a benzene has 4 **DBEs**!

  2. Shifts at 7.5 ands 7.4 are definitely not alkine protons. Aromatic protons are more likely, aren't they?
  3. Largest couplings between benzene protons are typically *ortho* couplings. How large are they in your case?
  4. Two sets of doublets at 7.5 and 7.4 ppm might indicate a 1,4-disubstituted benzene. You might want to play with some increment rules here.