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Secondary alkyl halides and strong base: Sn2 vs E2

I got this question from the PYQs of a college entrance exam. According to the answer key, 4-chloro-3-methylpent-1-ene reacts with NaOH in water to give 4-hydroxy-3-methylpent-1-ene via the SN2 ...
AADETYA JAISWAL's user avatar