Questions tagged [hydrides]

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13 votes
2 answers
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Could ammonium azanide exist?

In my first high school chemistry class, I misremembered nitrate as being $\ce{NH2-}$, rather than $\ce{NO3-}$, and wrote down a formula for "ammonium nitrate" that was $\ce{NH4NH2}$ (rather ...
Radvylf Programs's user avatar
1 vote
1 answer
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Is it not possible to prepare LAH using aluminium hydride?

Wikipedia lists this reaction for preparation of lithium aluminium hydride: $\ce{4 LiH + AlCl_3 -> Li[AlH_4] + 3 LiCl}$ But is it possible to prepare it by reacting aluminium hydride with lithium ...
Thecoder001's user avatar
1 vote
1 answer
176 views

Why does AsH3 have a higher boiling point than HBr?

Aside from the general trend of the boiling points of the hydrides, I noticed how the group 15 hydrides somehow "overtook" the group 17 ones in boiling point, which felt weird. Notably, H-...
nothingham's user avatar
3 votes
1 answer
219 views

Lithium aluminium hydride

Lithium aluminium hydride is an important reducing agent in organic chemistry. Since I cannot find the half-equations telling how this reducing agent performs its action, I am wondering, is lithium a ...
Chemistry is fun's user avatar
1 vote
1 answer
172 views

If diborane has 3c-2e bonds, then why are both boron atoms still electron deficit?

This is an image of the structure of diborane. It has a 3-center-2-electron bridge bond. As we can see in the bridge bond, the electron in the hydrogen atom and one electron in either boron atom is ...
Bongo Man's user avatar
  • 361
0 votes
1 answer
3k views

Ionic compounds with hydride anion [closed]

Ionic compounds are formed when an atom $\ce{A}$ donates one of it's electron to another atom $\ce{B}$ to form an ionic compound $\ce{A+B-}$. This is significantly more likely to happen as the ...
dotmashrc's user avatar
  • 373
8 votes
1 answer
9k views

Why can't NH5 form?

In ammonia a nitrogen atom forms 3 covalent bonds with hydrogen atoms and has one lone pair which can be used in a dative covalent bond with another hydrogen atom to form an ammonium ion. Instead of ...
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