All Questions
8 questions
16
votes
1
answer
3k
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Why is the dipole moment of chloromethane larger than the dipole moment of fluoromethane?
On the Pauling electronegativity scale, fluorine and chlorine are 3.98 and 3.16, respectively.
Since the dipole moment is dependent on electronegativity, why is the dipole moment of chloromethane ...
user16347
14
votes
4
answers
13k
views
Why does chloromethane have a larger dipole moment than chloroform?
Why does $\ce{CH3Cl}$, methyl chloride, have a larger dipole moment than $\ce{CHCl3}$, chloroform?
Let us consider $\ce{C-Cl}$ bond moment to be $x$ and that of $\ce{C-H}$ bond to be $y$.
In $\...
- 856
8
votes
1
answer
4k
views
Trend in the boiling point of the hydrogen halides
The boiling points of the hydrogen halides are as follows:
$$\begin{array}{cc}
\hline
\text{Species} & \text{Boiling point / }\mathrm{^\circ C} \\
\hline
\ce{HCl} & -85.1 \\
\ce{HBr} & -...
6
votes
3
answers
16k
views
Why is the dipole moment of ethyl chloride larger than that of vinyl chloride?
The dipole moment of ethyl chloride is 2.10 D (J. Mol. Struct. 1990, 216, 9–26), and that of vinyl chloride is 1.42 D (J. Chem. Phys. 1960, 32 (1), 205–209).
Why is this the case? I would have ...
- 61
4
votes
1
answer
428
views
Relative importance of electronegativity and bond length for dipole moment magnitude
In this answer to the question "Why is the dipole moment of chloromethane larger than the dipole moment of fluoromethane?", the order of the dipole moments was given as $\ce{CH3Cl > CH3F > CH3Br ...
- 3,226
3
votes
0
answers
76
views
Order of Polarities/Dipole Moments of CH3F, CH3Cl, CH3Br and CH3I [duplicate]
While explaining how to decide polarities/dipole moments of molecules, my teacher highlighted an exception to the statement:
For similar compounds like hydrides formed by different elements of a ...
- 243
1
vote
0
answers
128
views
Why London force dominates in Alkyl Halides
Why London Force is greater than dipole-dipole interactions in Alkyl Halides?
As we know that most of the time London force is weaker than other forces. Then why in this case it's not so?
...
- 21
0
votes
2
answers
103
views
Dipole-dipole vs London dispersion forces for deducing melting and boiling points
To determine the melting and boiling points of compounds, London dispersion forces are typically compared. However, why are the polarity and dipole-dipole forces ignored?
For instance, $\ce{HI}$ has a ...
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