Linked Questions

44
votes
8answers
27k views

Why do compounds like SF6 and SF4 exist but SH6 and SH4 don't?

Both $\ce{SF6}$ and $\ce{SH6}$ and $\ce{SF4}$ and $\ce{SH4}$ have the same central atom and the same hybridization, but my teacher specifically mentioned that $\ce{SH6}$ and $\ce{SH4}$ don't exist. I'...
23
votes
2answers
9k views

Sp5 hybridization in cyclopropane?

I have never before heard/read about something as a $sp^5$ hybridization. Today, Henry Rzepa's blog post made me aware of the existance of such a bonding system. That made me search a little bit and I ...
11
votes
3answers
7k views

Can Fe(CO)5 adopt both square pyramidal and trigonal bipyramidal geometries?

I know the hybridization of $\ce{Fe(CO)5}$ is $\mathrm{dsp^3}$. According to my book, coordination compounds with coordination number 5 can interchange between square pyramidal and trigonal ...
3
votes
1answer
18k views

How can the hybridisation schemes of transition metal complexes be determined?

Lets say I have to find hybridisation of $\ce{[Ni(CO)_4]}$ and $\ce{[Ni(CN)_4]^{2-}}$. The metal atom/ion in these compounds are $\rm Ni$ and $\rm Ni^{2+}$ respectively. So the outer shell ...
10
votes
1answer
1k views

Why are low spin tetrahedral complexes so rare?

As I was going through Concise Inorganic Chemistry by J. D. Lee, I realised that there are simply no low spin tetrahedral complexes mentioned in the book. Is there any specific condition required for ...
5
votes
1answer
7k views

Hybridisation of Co in [Co(ox)3]3-

Will the hybridisation of of $\ce{Co}$ in $\ce{[Co(ox)_3]^3-}$ be $\ce{ sp^3d^2}$ or $\ce{ d^2sp^3}$? The question in which I found it has mentioned the answer to be $\ce{d^2sp^3}$ while I was ...
3
votes
1answer
3k views

How do you determine the hybridisation state of a coordinate complex?

If an exercise asks for the hybridisation state of a coordinate complex (ion in solution) consisting of a central cobalt atom surrounded by $\ce{NH3}$ ligands, and neither coordination number or ...
4
votes
1answer
2k views

Why is the tetraamminecopper(II) ion square planar?

The tetraamminecopper(II) ion is square planar in shape. But why? How can I rationalise this? Can I rationalise this without the concept of hybridization? And even if I take hybridization into ...
3
votes
1answer
2k views

Hybridisation of complex compound having octahedral geometry

$$\ce{K[Co(NH3)2Cl4]}$$ I have problem finding the hybridisation of this compound. The strong field ligand $\ce{NH3}$ forms the minority among the ligands, so do I consider the hybridisation to be $\...
2
votes
0answers
1k views

Why are d orbitals used in the hybridisation of PCl5 and similar compounds? [duplicate]

Phosphorus uses its $\ce{3s}$, three $\ce{3p}$ and one $\ce{3d}$ orbitals for its hybridization in $\ce{PCl5}$ and similar compounds. However, shouldn't it use its $\ce{4s}$ rather than $\ce{3d}$ ...
4
votes
2answers
557 views

Considering the d-d transition how, does tetracyanidonickelate(II) ion exist as a colored complex?

As I refer on google, the resources indicated that, the d block elements which have unpaired electrons as in their ions, when they are making complexes with ligands, they can absorb different ...
3
votes
1answer
503 views

Why energy of all d orbitals is same?

This question first popped up in my head when I learnt that $d_{z^2}$ orbital is used in $sp^3d$ hybridization and $d_{x^2-y^2}$ and $d_{z^2}$ orbitals are used in $sp^3d^2$ hybridization. If all ...
5
votes
0answers
305 views

Unconventional hybridisation states

I just came across a table with interesting hybridisation schemes I have never seen before. The table is shown below. I was wondering if anyone could give me some examples of atoms in particular ...
0
votes
0answers
86 views

What is the electronic structure of Mn in KMnO4 and K2MnO4?

I know that is is d3s hybrid. But in my book it is unclear which orbitals participate in pi bond with O. I think it should be both p and d orbitals of Mn that do.
0
votes
0answers
79 views

Why are d(xy),d(yz) and d(xz) orbitals involved in d³s hybridisation?

Shouldn't d(x²-y²) dxy and dz² orbitals participate? Since this corressponds to the best case overlap? What factors decide the participating orbitals in hybridisation? P.S I am well versed with the ...

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