Linked Questions

-2 votes
1 answer
917 views

What is the hybridisation of [Co(H₂O)₆]³⁺? [duplicate]

There's a lot of ambiguity in the hybridisation of $\ce{Co^3+}$ in its hexaaqua complex; is it a high spin or low spin complex? As theoretically the CFSE is less than P so it should be low spin, but ...
Nisarg Chadha's user avatar
65 votes
9 answers
42k views

Why do compounds like SF6 and SF4 exist but SH6 and SH4 don't?

Both $\ce{SF6}$ and $\ce{SH6}$ and $\ce{SF4}$ and $\ce{SH4}$ have the same central atom and the same hybridization, but my teacher specifically mentioned that $\ce{SH6}$ and $\ce{SH4}$ don't exist. I'...
sayantankhan's user avatar
33 votes
2 answers
17k views

Sp5 hybridization in cyclopropane?

I have never before heard/read about something as a $sp^5$ hybridization. Today, Henry Rzepa's blog post made me aware of the existance of such a bonding system. That made me search a little bit and I ...
pH13 - Yet another Philipp's user avatar
14 votes
3 answers
14k views

Can Fe(CO)5 adopt both square pyramidal and trigonal bipyramidal geometries?

I know the hybridization of $\ce{Fe(CO)5}$ is $\mathrm{dsp^3}$. According to my book, coordination compounds with coordination number 5 can interchange between square pyramidal and trigonal ...
user avatar
4 votes
1 answer
29k views

How can the hybridisation schemes of transition metal complexes be determined?

Lets say I have to find hybridisation of $\ce{[Ni(CO)_4]}$ and $\ce{[Ni(CN)_4]^{2-}}$. The metal atom/ion in these compounds are $\rm Ni$ and $\rm Ni^{2+}$ respectively. So the outer shell ...
user8277998's user avatar
11 votes
1 answer
4k views

Why are low spin tetrahedral complexes so rare?

As I was going through Concise Inorganic Chemistry by J. D. Lee, I realised that there are simply no low spin tetrahedral complexes mentioned in the book. Is there any specific condition required for ...
evamPUNdit's user avatar
8 votes
1 answer
18k views

Hybridisation of cobalt in tris(oxalato)cobaltate(III)

Will the hybridisation of of $\ce{Co}$ in $\ce{[Co(C2O4)3]}^{3-}$ be $\mathrm{sp^3d^2}$ or $\mathrm{d^2sp^3}$? The question in which I found it has mentioned the answer to be $\mathrm{d^2sp^3}$ while ...
Piyush Maheshwari's user avatar
4 votes
1 answer
5k views

How do you determine the hybridisation state of a coordinate complex?

If an exercise asks for the hybridisation state of a coordinate complex (ion in solution) consisting of a central cobalt atom surrounded by $\ce{NH_3}$ ligands, and neither coordination number or ...
Nicolas Derie's user avatar
6 votes
2 answers
3k views

Possible structure if a compound like AB4 is polar?

I was asked the following question in JEE Mains (2nd September, Shift 1) 2020, If a compound AB4 is polar (having non-zero dipole moment), then it's structure could be (A) Square planar (B) ...
Rahul Verma's user avatar
  • 3,071
10 votes
1 answer
3k views

Shape of nickel tetracarbonyl

Is nickel tetracarbonyl a square planar complex or a tetrahedral complex? According to the crystal field theory, $\ce{CO}$ is a strong field ligand and should hence cause the $t_{2g}$ electrons of ...
user122143's user avatar
5 votes
1 answer
3k views

Does Fe(CO)6 really exist?

I was given a question to draw the structure of $\ce{Fe(CO)6}$ and tell the hybridization. Hybridization came out to be $\ce{sp^3d^2}$ and structure as Octahedral. But does $\ce{Fe(CO)6}$ really exist?...
Danish Juneja's user avatar
6 votes
1 answer
5k views

Why is the tetraamminecopper(II) ion square planar?

The tetraamminecopper(II) ion is square planar in shape. But why? How can I rationalise this? Can I rationalise this without the concept of hybridization? And even if I take hybridization into ...
Kawsar Ahmed's user avatar
3 votes
2 answers
1k views

Explain on the basis of valence bond theory that tetracyanonickelate(II) ion with square planar structure is diamagnetic

Answers on the internet suggest that tetracyanonickelate ($\ce{([Ni(CN)4]^{2-}}$) with square planar structure is diamagnetic because $\ce{CN-}$ is a strong field ligand and causes pairing, but my ...
Kumar Mayank's user avatar
4 votes
1 answer
3k views

Which d orbitals are involved in "d3s hybridisation"?

I was reading about hybridisation and came across a point saying that $\mathrm{d^3s}$ hybridisation involves only $\mathrm d_{xy}$, $\mathrm d_{yz}$, and $\mathrm d_{zx}$ orbitals and not $\mathrm d_{...
Videsh .V.K's user avatar
4 votes
2 answers
332 views

Hybridisation of similar energy orbitals

Hybridisation is the mixing of orbitals of similar energies, so when we perform hybridisation, why don't we prefer $4\mathrm s$ in place of the $3\mathrm d$ orbital for hybridisation, even though $4\...
Paras Bisht's user avatar

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