Linked Questions

1 vote
0 answers

What is the exact statement of Drago's rule? [duplicate]

While studying the topic of chemical bonding, I came across a statement given by my teacher: Elements of the third period and above do not show hybridisation. An example, in the case of $\ce{PH_3}$, $...
sfsg's user avatar
  • 55
65 votes
8 answers

Why do compounds like SF6 and SF4 exist but SH6 and SH4 don't?

Both $\ce{SF6}$ and $\ce{SH6}$ and $\ce{SF4}$ and $\ce{SH4}$ have the same central atom and the same hybridization, but my teacher specifically mentioned that $\ce{SH6}$ and $\ce{SH4}$ don't exist. I'...
sayantankhan's user avatar
41 votes
3 answers

Why is the bond angle H-P-H smaller than H-N-H?

$\ce{N}$ & $\ce{P}$ are in the same group. Both $\ce{NH3}$ and $\ce{PH3}$ have one lone pair and according to VSEPR theory, both the central atoms are predicted to be $\ce{sp^3}$ hybridized. But ...
user avatar
17 votes
4 answers

Hybridization of nitrogen in trisilylamine, (SiH3)3N?

I want to know the hybridization of the central atom in $\ce{(SiH3)3N}$. I think it should be $\mathrm{sp^3}$, because $\ce{N}$ is attached to three silicon atoms and one lone pair. But actually it ...
hey's user avatar
  • 195
9 votes
2 answers

Hybridization in PH3

Does $\ce{PH3}$ exhibit $\ce{sp^3}$ hybridization? Arguments against hybridization: $\ce{PH3}$ is less basic than $\ce{NH3}$. This jibes with the supposition that $\ce{PH3}$ keeps its lone pair in ...
Dissenter's user avatar
  • 18.8k
6 votes
1 answer

Why are axial bonds are longer than equatorial bond in sp3d hybridized atoms?

Why are axial bonds are longer than equatorial bond in case of $\mathrm{sp^3d}$ hybridization? I have done some research but I can't seem to find the answer.
RAUSHAN KUMAR's user avatar
14 votes
1 answer

Mathematical relation between bond angle and fraction of s or p character

In Concise Inorganic Chemistry by J.D.Lee (Adapted by Sudarsan Guha, Fourth Edition), on page 75, under the topic "Effect of Electronegativity - When the surrounding atom is same with different ...
Vishnu's user avatar
  • 2,050
12 votes
3 answers

Bond angle order of SF2, OF2, HOF

Arrange the following componds in the increasing order of bond angle. $$\ce{HOF,~OF2,~SF2}$$ I know that bond angle of $\ce{SF2}$ will be less than the bond angle of $\ce{OF2}$ because of larger ...
Aditya Dev's user avatar
  • 7,786
3 votes
3 answers

How can I tell if a molecule is polar or not?

Consider $\ce{PCl3}$, $\ce{CH2Cl2}$, $\ce{HCN}$, and $\ce{SiO2}$. Which of these molecules are polar substances? I appear to be lacking on the concept of "polar substance". I was just studying about ...
Saturn's user avatar
  • 835
4 votes
2 answers

Is ClH7 possible? [duplicate]

Chlorine can be $sp^3d^3$ hybridized. If so, it can form $\ce{ClH_7}$ and then chlorine, being more electronegative, will have (-7) as its oxidation number. But we know that the oxidation number of $\...
Ayan Biswas's user avatar
1 vote
2 answers

Why the formation of PH4+ is difficult compared to NH4+? [duplicate]

My textbook asks this as an objective question. What I had in mind was that the lone pair on phosporous was more distributed as compared to nitrogen(since nitrogen is more electronegative and smaller ...
Stan's user avatar
  • 145
-1 votes
2 answers

Do PH3F2 and XeS2 exist (in the light of hybridisation and Valence Bond Theory)? [Doubt in JEE question]

Do $\ce{PH3F2}$ and $\ce{XeS2}$ exist, in accordance with Valence Bond Theory? According to Drago's Rule, if the central atom of a compound is an element of the third period, and the attached atom has ...
Bongo Man's user avatar
  • 361
1 vote
0 answers

How to explain shape of molecules in penta and hexa coordination if hybridization involving d-orbitals (in main block) is considered incorrect?

In this answer @Jan says: penta- and hexacoordination; tetracoordination with additional lone pairs and related: attempt to form as many normal bonds with p orbitals as possible; keep one lone ...
user avatar
4 votes
1 answer

Clarification needed regarding description of molecules without hybridization using pure p orbitals

I need some clarification regarding this answer given by the user @Jan. @Jan says: Therefore, the a priori predicted most stable configurations of certain coordination numbers are: ...
user avatar