Let's say we have solute a, which is highly concentrated (let's say 99%?) on side 1 of a semipermeable membrane.

We also have solute b, which is has a much lower concentration (let's say 0.01%) on side 2 of a semipermeable membrane.

If we allow these two solutes to diffuse across a semi-permeable membrane that permits both, my reading seems to suggest that we would eventually expect 50% of solute a to occur on side 1 and 50% on side 2. We would also expect 50% of solute b to occur on side 1 and 50% on side 2.

I'm not sure that I understand this.

I completely agree that 50% of the a+b molecules will end up on side 1 and 50% of a+b will end up on side 2.

But I don't understand why different solutes travel along their own concentration gradients independent of other solutes in solution. Why would they not interact with the other solute?

Perhaps they do, and the diffusion kinetics of solute a would dictate that it reaches equilibrium much faster than solute b?

Would it be correct to predict that the larger the difference in initial global concentration, the longer the lag between when "a" reaches equilibrium vs. when "b" reaches equilibrium?

  • $\begingroup$ In a lot of such problems in chemistry the concentration is often used instead of the more appropriate thermodynamic activity. The deviation between activity and concentration tends to become larger with increasing concentration, but there are exceptions. // I think activities are generally ignored because they can't be calculated a priori and using them makes the calculations messy. No problem for a computer doing a numerical analysis, but very difficult to use when doing hand calculations. $\endgroup$
    – MaxW
    Jul 16 '18 at 3:48
  • $\begingroup$ This happens because the species do not interact with one another. They just collide with solvent and any other species present (a and or b) and spread out randomly ( 'driven' via entropy of mixing) until equilibrium is established. Then at equilibrium just as many diffuse left to right as the other way round, so always diffusing. If a precipitate was formed on contact, say, between a and b then one species might all be used up leaving the remainder again free to diffuse until a new equilibrium is established. $\endgroup$
    – porphyrin
    Jul 16 '18 at 7:04

If we assume that the solvent is the same on both sides of the membrane (or that the solvent itself can penetrate the membrane) then the final equilibrium will have the same concentration across the membrane. That only translates to "50% of solute b to occur on side 1 and 50% on side 2" if the volumes are equal.

The rate at which solute A moves from left to right is proportional to the rate at which molecules of solute A on the left side randomly collide with the membrane. This is proportional to the concentration of A in the left side solution. The presence of molecules for solute B does not affect this process.

The reverse process is also happening with molecules diffusing from right to left at a rate proportional to their concentration in the right side solution. As the concentration on the right side increases to be equal to the concentration on the left, so the diffusion rates become equal and there is zero nett diffusion and the system approaches equilibrium.

Note that this assumes a "perfect" system where there is no chemical reaction occurring between the solutes or between the solutes and the membrane. In practice this means that either the interaction between solutes A and B is the same as the interaction between the solutes and the solvent or that the solute molecules are so greatly outnumbered by the solvent molecules that the solute-solute interactions are not significant.

The rate of diffusion of solute A may be different from B (i.e. the proportionality constant between rate and concentration may be different). This means that before reaching equilibrium the relative concentrations of A and B may change but at equilibrium, the relative concentration will be the same as initially.

If we define "reaching equilibrium" as having some fraction (say 99.99%) of the final concentration then increasing the initial global concentration will increase the lag for both solutes equally and will not change their relative concentrations.


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