While solving a few questions from interphase mass transfer I came across this question. The question stated that when oxygen is being absorbed from air to water it is a liquid phase resistance controlled process. And the question was which phase would offer the controlling resistance if oxygen was being absorbed in a strong pyrogallate solution. From my understanding I inferred that since Oxygen is very soluble in pyrogallol the controlling resistance would in this case lie in the gas phase. But the answer in the book is given as liquid phase resistance controlled process. Where in my line of thought have I made a mistake ? Or is it that the answer given is wrong ?

  • $\begingroup$ What gave you idea such as " Oxygen is very soluble in pyrogallol "? Even if it was, it's still aqueous solution. Oh, you probably didn't take into account that O2 reacts with pirogallol and thought it's just some normal dissolving on steroids? $\endgroup$ – Mithoron Jul 9 '18 at 21:00
  • $\begingroup$ @Mithoron LoL thank you for your insight.. I just knew that O2 is absorbed using pyrogallol. Thank you for shedding some light on it. I think you have answered my question. Since O2 reacts with pyrogallol which is why its used to absorb O2 , because the O2 has to react with pyrogallol the resistance still lies in the liquid phase. Thank You $\endgroup$ – Sambuddha Mookherji Jul 10 '18 at 2:02
  • $\begingroup$ @Mithoron But I would really like a proper answer to my question. And whether I am thinking in the correct direction. $\endgroup$ – Sambuddha Mookherji Jul 11 '18 at 16:50
  • $\begingroup$ You don't need to ping if only one user commented under your post. The problem with your question seems to be strange wording. I wouldn't use a word "resistance" $\endgroup$ – Mithoron Jul 11 '18 at 17:06
  • $\begingroup$ its a question from interphase mass transfer. I did not make up the word resistance. It was in the question. And also the book I am following is Mass transfer by Robert Treybal. There the resistance to mass transfer is the inverse of the mass transfer coefficient. You can look it up. $\endgroup$ – Sambuddha Mookherji Jul 12 '18 at 11:01

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