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Why does 2-pyridone react with chlorine to give 3,5-dichloro-2-pyridone? I thought that 2-pyridone is resistant and will yield only 5-chloro-2-pyridone or even a combination with 3-chloro-2-pyridone

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    $\begingroup$ resistant does not mean it does not react $\endgroup$ – Waylander Jul 3 '18 at 13:14

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