I need help identifying the following 5 substances; G, Y, T, L and J
G is a white solid which is insoluble in water. Consider the following reactions carried out on solid G.
Step 1:
Excess dilute nitric acid is added to a small amount of G in a test-tube. A colourless and odourless gas Y is given off and it is noticed that Y extinguishes a lighted splint.
The solution remaining in the test tube is divided into two different test tubes, sample A and sample B.
Step 2:
A few drops of potassium iodide solution are added to a sample A and a bright yellow precipitate L is observed.
Step 3:
Sodium hydroxide solution is added drop wise to sample B. A dense white precipitate, T, is immediately observed. Precipitate T dissolves when excess sodium hydroxide solution is added to it.
Step 4:
When some G is heated in a hard glass tube, gas Y which is colourless and odourless is given off. The solid J remaining in the hard glass tube changes colour on cooling from red-brown to yellow.
These are my solutions:
- G = $\ce{PbCO3}$ because
- Y = $\ce{CO2}$ - colourless and odourless gas
- L = $\ce{PbI2}$
- T = $\ce{Pb(OH)2}$
- J = $\ce{PbO2}$
Are they correct or not?